File Name: 100 great problems of elementary mathematics their history and solution .zip
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A book collecting the celebrated problems of elementary mathematics that would commemorate their origin and, above all, present their solutions briefly, clearly, and comprehensibly has long seemed a necessary and attractive task to the author. The restriction to problems of elementary mathematics was considered advisable in view of those readers who have neither the time nor the opportunity to acquaint themselves in any detail with higher mathematics.
Nevertheless, in spite of this limitation a colorful and compelling picture has emerged, one that gives an idea of the amazing variety of mathematical methods and one that will—I hope—enchant many who are interested in mathematics and who take pleasure in characteristic mathematical thought processes.
In the present work there are to be found many pearls of mathematical art, problems the solutions of which represent, in the achievements of a Gauss, an Euler, Steiner, and others, incredible triumphs of the mathematical mind. Because the difficult economic situation at the present time barred the publication of a larger work, a limit had to be set to the scope and number of the problems treated.
Thus, I decided on a round number of one hundred problems. Moreover, since many of the problems and solutions require considerable space despite the greatest concision, this had to be compensated for by the inclusion of a number of mathematical miniatures.
Possibly, however, it may be just these little problems, which are, in their way, true jewels of mathematical miniature work, that will find the readiest readers and win new admirers for the queen of the sciences. As we have indicated already, a knowledge of higher analysis is not assumed.
Consequently, the Taylor expansion could not be used for the treatment of the important infinite series. I hope nonetheless that the derivations we have given, particularly the striking derivation of the sine and cosine series, will please and will not be found unattractive even by mathematically sophisticated readers.
On the other hand, in some of the problems, e. The characteristic advantages of brevity and elegance of the vector method are so obvious, and the time and effort required for mastering it so slight, that the vectorial methods presented here will undoubtedly spur many readers on to look into this attractive area. For the rest, only the theorems of elementary mathematics are assumed to be known, so that the reading of the book will not entail significant difficulties. In this connection the inclusion of the little problems may in fact increase the acceptability of the book, in that it will perhaps lead the mathematically weaker readers, after completion of the simpler problems, to risk the more difficult ones as well.
So then, let the book go out and do its part to awaken and spread the interest and pleasure in mathematical thought.
The second edition of the book contains few changes. The sun god had a herd of cattle consisting of bulls and cows , one part of which was white , a second black , a third spotted , and a fourth brown.
Among the bulls , the number of white ones was one half plus one third the number of the black greater than the brown; the number of the black , one quarter plus one fifth the number of the spotted greater than the brown; the number of the spotted , one sixth and one seventh the number of the white greater than the brown. Among the cows , the number of white ones was one third plus one quarter of the total black cattle; the number of the black , one quarter plus one fifth the total of the spotted cattle; the number of the spotted , one fifth plus one sixth the total of the brown cattle; the number of the brown , one sixth plus one seventh the total of the white cattle.
If we use the letters X , Y , Z , T to designate the respective number of the white, black, spotted, and brown bulls and x , y , z , t to designate the white, black, spotted, and brown cows, we obtain the following seven equations for these eight unknowns:.
Since and possess no common factors, T must be some whole multiple—let us say G —of If these values are substituted into equations 4 , 5 , 6 , 7 , the following equations are obtained:. These equations are solved for the four unknowns x , y , z , t and we obtain. Since none of the coefficients of G on the right can be divided by c , then G must be an integral multiple of c :. If this value of G is introduced into I and II , we finally obtain the following relationships:.
The problem therefore has an infinite number of solutions. If g is assigned the value 1, we obtain the following:. As the above solution shows, the problem of the cattle cannot properly be considered a very difficult problem, at least in terms of present concepts. Here the problem is posed in the following poetic form, made up of twenty-two distichs, or pairs of verses:.
Lessing, however, disputed the authorship of Archimedes. The distinguished Danish authority on Archimedes J. Heiberg Quaestiones Archimedeae , the French mathematician P. XXV, , on the other hand, are of the opinion that this complete form of the problem is to be attributed to Archimedes.
If we substitute in 8 and 9 the values X , Y , Z , T in accordance with I , these equations are transformed into. This is a so-called Fermat equation, which can be solved in the manner described in Problem The solution is, however, extremely difficult because d has the inconveniently large value.
A merchant had a forty-pound measuring weight that broke into four pieces as the result of a fall. When the pieces were subsequently weighed , it was found that the weight of each piece was a whole number of pounds and that the four pieces could be used to weigh every integral weight between 1 and 40 pounds. We can distinguish the two scales of the balance as the weight scale and the load scale.
On the former we will place only pieces of the measuring weight; whereas on the load scale we will place the load and any additional measuring weights. If we are to make do with as few measuring weights as possible it will be necessary to place measuring weights on the load scale as well. For example, in order to weigh one pound with a two-pound and a three-pound piece, we place the two-pound piece on the load scale and the three-pound piece on the weight scale. If we single out several from among any number of weights lying on the scales, e.
We will consider only integral loads and measuring weights, i. If we have a series of measuring weights A , B , C , …, which when properly distributed upon the scales enable us to weigh all the integral loads from 1 through n lbs, and if P is a new measuring weight of such nature that its weight p exceeds the total weight n of the old measuring weights by 1 more than that total weight :.
In fact, the old pieces are sufficient to weigh all loads from 1 to n lbs. In order to carry out the maximum possible number of weighings with two measuring weights, A and B , A must weigh 1 lb and B 3 lbs. These two pieces enable us to weigh loads of 1, 2, 3, 4 lbs. In Volume 21 of the Quarterly Journal of Mathematics MacMahon determined all the conceivable sets of integral weights with which all loads of 1 to n lbs can be weighed.
It is assumed that all the fields provide the same amount of grass, that the daily growth of the fields remains constant, and that all the cows eat the same amount each day. Let the initial amount of grass contained by each field be M , the daily growth of each field m , and the daily grass consumption of each cow Q.
And this value must be equal to zero, since the fields are grazed bare in c days. This gives rise to the equation. If 1 and 2 are taken as linear equations for the unknowns M and m , we obtain. The solution is more easily seen when expressed in the form of determinants. If q represents the reciprocal of Q , equations 1 , 2 , 3 assume the form. According to one of the basic theorems of determinant theory, the determinant of a system of n 3 in this case linear homogeneous equations possessing n unknowns that do not all vanish M , m , q in this case must be equal to zero.
Consequently, the desired relation has the form. In the following division example , in which the divisor goes into the dividend without a remainder:. What are the missing numbers? This remarkable problem comes from the English mathematician E.
Berwick, who published it in in the periodical The School World. We will assign a separate letter to each of the missing numerals. The example then has the following appearance:. Since the remainders in the third and seventh lines possess six numerals, F must equal 1 and R must equal 1, as a result of which f and r must also equal 1 according to the outline.
And since S can only be 9 or 0, and since there is no remainder in the ninth line under s , only the second case is possible. The possibility of equaling I must, therefore, be discarded. With the results obtained at this point the problem has the following appearance:. This presents ten different possibilities. This gives the problem the following appearance:.
In a boarding school there are fifteen schoolgirls who always take their daily walks in rows of threes. How can it be arranged so that each schoolgirl walks in the same row with every other schoolgirl exactly once a week?
Of the great number of solutions that have been found we will reproduce two. XI, ; the other is that of B. VI, — Mathematically expressed the problem consists of arranging the fifteen elements x , a 1 a 2, b 1, b 2, c 1, c 2, d l, d 2, e 1, e 2, f 1, f 2, g 1, g 2 in seven columns of five triplets each in such a way that any two selected elements always occur in one and only one of the 35 triplets. As the initial triplets of the seven columns we shall select:. Then we have only to distribute the 14 elements a l, a 2, b l, b 2, …, g 1, g 2 correctly over the other four lines of our system.
Using the seven letters a , b , c , d , e , f , g , we form a group of triplets in which each pair of elements occurs exactly once, specifically the group:. The triplets are in alphabetical order. From this group it is possible to take for each column exactly four triplets that contain all the letters except those contained in the first line of the column.
If we then place the appropriate triplets in alphabetical order in each column, we obtain the following preliminary arrangement:. Now we have to index the triplets bdf , beg , cdg , cef , ade , afg , abc , i.
We index them in the order just mentioned, i. When a letter in one column has received its index number, the next time that letter occurs in the same column it receives the other index number.
If two letters of a triplet have already been assigned index numbers, these two index numbers must not be used in the same sequence for the same letters in other triplets. If the index number of a letter is not determined by rules I. First step. The triplets bdf , beg , cdg , and all the letters aside from a that can be indexed in accordance with this numbering system and rules I.
Second step. The missing index numbers in boldface in the diagram of the triplets ade and afg , as well as the index numbers obtained in accordance with rule I. Third step. This method results in the following completed diagram, which represents the solution of the problem. Open navigation menu. Close suggestions Search Search. User Settings. Skip carousel. Carousel Previous.
Archimedes' cattle problem, also called the bovinum problema, or Archimedes' reverse, is stated as follows: "The sun god had a herd of cattle consisting of bulls and cows, one part of which was white, a second black, a third spotted, and a fourth brown. Among the bulls, the number of white ones was one half plus one third the number of the black greater than the brown; the number of the black, one quarter plus one fifth the number of the spotted greater than the brown; the number of the spotted, one sixth and one seventh the number of the white greater than the brown. Among the cows, the number of white ones was one third plus one quarter of the total black cattle; the number of the black, one quarter plus one fifth the total of the spotted cattle; the number of spotted, one fifth plus one sixth the total of the brown cattle; the number of the brown, one sixth plus one seventh the total of the white cattle. What was the composition of the herd? Solution consists of solving the simultaneous Diophantine equations in integers , , , the number of white, black, spotted, and brown bulls and , , , the number of white, black, spotted, and brown cows ,. A more complicated version of the problem requires that be a square number and a triangular number. The solutions to this problem are numbers with or digits, which was first obtained by Williams et al.
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Book page image Great Problems of Elementary Mathematics THEIR HISTORY AND SOLUTION Heinrich Dorrie Translated by David Antin.
Since the Renaissance , every century has seen the solution of more mathematical problems than the century before, yet many mathematical problems, both major and minor, still remain unsolved. Some problems may belong to more than one discipline of mathematics and be studied using techniques from different areas. Prizes are often awarded for the solution to a long-standing problem, and lists of unsolved problems such as the list of Millennium Prize Problems receive considerable attention.
A book collecting the celebrated problems of elementary mathematics that would commemorate their origin and, above all, present their solutions briefly, clearly, and comprehensibly has long seemed a necessary and attractive task to the author. Nevertheless, in spite of this limitation a colorful and compelling picture has emerged, one that gives an idea of the amazing variety of mathematical methods and one that will—I hope—enchant many who are interested in mathematics and who take pleasure in characteristic mathematical thought processes. In the present work there are to be found many pearls of mathematical art, problems the solutions of which represent, in the achievements of a Gauss, an Euler, Steiner, and others, incredible triumphs of the mathematical mind. Because the difficult economic situation at the present time barred the publication of a larger work, a limit had to be set to the scope and number of the problems treated.
Foster critical thinking skills with practice problems, video hints, and full step-by-step solutions, all clearly aligned with Common Core standards. Fine Arts: Theater. From the French by Thomas J.
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ВЫ УВЕРЕНЫ. Он снова ответил Да. Мгновение спустя компьютер подал звуковой сигнал. СЛЕДОПЫТ ОТОЗВАН Хейл улыбнулся.
Я собирался передать всю эту информацию в прессу. Сердце у Сьюзан бешено забилось. Правильно ли она поняла. Все сказанное было вполне в духе Грега Хейла. Но это невозможно.
Buy Great Problems of Elementary Mathematics (Dover Books on witness to the extraordinary ingenuity of some of the greatest mathematical minds of history The Stanford Mathematics Problem Book: With Hints and Solutions (Dover This is in contrast to the bulk of math problem books out there that just deal with.
Фонтейн не мог в это поверить. - Вы полагаете, что Танкадо хотел остановить червя. Вы думаете, он, умирая, до последний секунды переживал за несчастное АНБ. - Распадается туннельный блок! - послышался возглас одного из техников. - Полная незащищенность наступит максимум через пятнадцать минут. - Вот что я вам скажу, - решительно заявил директор. - Через пятнадцать минут все страны третьего мира на нашей планете будут знать, как построить межконтинентальную баллистическую ракету.
Весь мир для нее превратился в одно смутное, медленно перемещающееся пятно. Увидев их, Джабба сразу превратился в разъяренного быка: - Я не зря создал систему фильтров. - Сквозь строй приказал долго жить, - безучастно произнес Фонтейн. - Это уже не новость, директор.
Она снова почувствовала себя школьницей. Это чувство было очень приятно, ничто не должно было его омрачить. И его ничто не омрачало. Их отношения развивались медленно и романтично: встречи украдкой, если позволяли дела, долгие прогулки по университетскому городку, чашечка капуччино у Мерлутти поздно вечером, иногда лекции и концерты. Сьюзан вдруг поняла, что стала смеяться гораздо чаще, чем раньше.
Когда санитары отвезли тело Танкадо в морг, офицер попытался расспросить канадца о том, что произошло. Единственное, что он понял из его сбивчивого рассказа, - это что перед смертью Танкадо отдал кольцо. - Танкадо отдал кольцо? - скептически отозвалась Сьюзан. - Да.
Глаза немца расширились.
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